Folding Lists

fold() combines all elements of a list in order to produce a single result.

A common puzzle is to implement an operation such as sum() or reverse() using fold(). Here, fold() sums a sequence:

// FoldingLists/SumViaFold.kt import atomictest.eq fun main(args: Array<String>) { val list = listOf(1, 10, 100, 1000) list.fold(0) { sum, n -> sum + n } eq 1111 }

fold() takes the initial value (its argument) and successively applies the operation (expressed here as a lambda) to combine the current accumulated value with each element. In this example, the initial value is 0. fold() first adds 0 and 1 to get 1. That becomes the sum, which is added to the 10 to get 11, which becomes the new sum. The operation is repeated for two more elements: 100 and 1000. This produces 111 and 1111. fold() stops when there is nothing else in the list, returning the final sum of 1111. Of course, Kotlin doesn’t really know it’s doing a “sum”—the choice of identifier name was ours, to make it easier to understand.

End of sample. See AtomicKotlin.com for full early-access book.



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